Find the 2×2 grids in the given 5×5 grid where sum is the maximum. To list the answer, follow row element1, row element2 ; col element1, col element2 to represent the answer. Ex. 41, 24; 56, 92
📌 Challenge Details and Links
ExcelBI Excel Challenge Number: 514
Challenge Difficulty: ⭐️
📥Download Sample File
📥Link to the solutions on LinkedIn
Solving the challenge of Max 2×2 Grid Sum with Power Query
Power Query solution 1 for Max 2×2 Grid Sum, proposed by Aditya Kumar Darak 🇮🇳:
let
Source = Excel.CurrentWorkbook(){[Name = "data"]}[Content],
ToRow = Table.ToRows(Source),
Count = List.Count(ToRow) - 2,
Generate = List.TransformMany(
{0 .. Count},
(x) => {0 .. Count},
(x, y) => [
Rng = List.Range(ToRow{x}, y, 2) & List.Range(ToRow{x + 1}, y, 2),
S = List.Sum(Rng),
T = List.Transform(Rng, Text.From),
R = T{0} & ", " & T{1} & "; " & T{2} & ", " & T{3}
]
),
Max = List.Max(Generate, null, each [S])[S],
Filter = List.Transform(Generate, each if [S] = Max then [R] else null),
Return = List.RemoveNulls(Filter)
in
Return
Power Query solution 2 for Max 2×2 Grid Sum, proposed by Ramiro Ayala Chávez:
let
S = Excel.CurrentWorkbook(){[Name = "Table1"]}[Content],
a = List.Combine(Table.ToRows(S)),
b = List.Skip(
List.Generate(
() => [i = 0, j = {}],
each [i] < List.Count(a),
each [i = [i] + 1, j = List.Range(a, [i], 2) & List.Range(a, [i] + 5, 2)],
each [j]
)
),
c = List.Select(b, each List.Count(_) = 4),
d = List.RemoveRange(List.RemoveRange(List.RemoveRange(c, 4), 4 * 2), 4 * 3),
e = Table.FromRows(List.Transform(d, each _ & {List.Sum(_)})),
f = Table.MaxN(Table.Group(e, {"Column5"}, {"G", each _}), "Column5", 1)[[G]],
g = Table.RemoveColumns(Table.Combine(f[G]), "Column5"),
h = Table.TransformColumnTypes(
g,
{{"Column1", type text}, {"Column2", type text}, {"Column3", type text}, {"Column4", type text}}
),
Sol = Table.AddColumn(
h,
"Answer Expected",
each [Column1] & ", " & [Column2] & " ; " & [Column3] & ", " & [Column4]
)[[Answer Expected]]
in
Sol
Power Query solution 3 for Max 2x2 Grid Sum, proposed by Mihai Radu O:
let
Source = Excel.CurrentWorkbook(){[Name = "Table1"]}[Content],
s = [
nrC = Table.ColumnCount(Source),
a = List.Transform(List.Combine(Table.ToRows(Source)), Text.From),
b = List.Select(
List.Transform(
{0 .. List.Count(a) - 1},
(x) => try a{x} & ", " & a{x + 1} & "; " & a{x + nrC} & ", " & a{x + nrC + 1} otherwise null
),
each _ <> null
),
c = List.Transform(Table.ToColumns(Source){nrC - 1}, Text.From),
d = List.Select(b, (x) => not List.Contains(c, Text.BeforeDelimiter(x, ","))),
e = List.Transform(
d,
(x) => List.Sum(List.Transform(Text.SplitAny(x, ";,"), (y) => Number.From(Text.Trim(y))))
),
f = Table.SelectRows(Table.FromColumns({d, e}), each [Column2] = List.Max(e))[Column1]
][f]
in
s
Solving the challenge of Max 2x2 Grid Sum with Excel
Excel solution 1 for Max 2x2 Grid Sum, proposed by Bo Rydobon 🇹🇭:
=LET(
z,
B2:F6,
m,
LAMBDA(
f,
MAKEARRAY(
ROWS(
z
)-1,
COLUMNS(
z
)-1,
LAMBDA(
r,
c,
f(
INDEX(
z,
r+{0;1},
c+{0,
1}
)
)
)
)
),
s,
m(
SUM
),
SUBSTITUTE(
TOCOL(
IFS(
s=MAX(
s
),
m(
ARRAYTOTEXT
)
),
3
),
",",
";",
2
)
)
Excel solution 2 for Max 2x2 Grid Sum, proposed by Bo Rydobon 🇹🇭:
=LET(m,LAMBDA(f,MAP(B2:E5,LAMBDA(x,f(OFFSET(x,,,2,2))))),s,m(SUM),SUBSTITUTE(TOCOL(IFS(s=MAX(s),m(ARRAYTOTEXT)),3),",",";",2))
for non Beta
=LET(m,LAMBDA(y,MAP(B2:E5,LAMBDA(x,LET(o,OFFSET(x,,,2,2),IF(y,SUM(o),ARRAYTOTEXT(o)))))),s,m(1),SUBSTITUTE(TOCOL(IFS(s=MAX(s),m(0)),3),",",";",2))
Excel solution 3 for Max 2x2 Grid Sum, proposed by Rick Rothstein:
=LET(
d,
DROP(
REDUCE(
"",
B2:E5,
LAMBDA(
a,
x,
VSTACK(
a,
TOROW(
OFFSET(
x,
0,
0,
2,
2
)
)
)
)
),
1
),
b,
BYROW(
d,
LAMBDA(
r,
SUM(
r
)
)
),
BYROW(
FILTER(
d,
b=MAX(
b
)
),
LAMBDA(
r,
TEXTJOIN(
{", ",
"; ",
", "},
,
r
)
)
)
)
Excel solution 4 for Max 2x2 Grid Sum, proposed by John V.:
=LET(
x,
B2:E5,
y,
C3:F6,
i,
MAP(
x,
y,
LAMBDA(
a,
b,
SUM(
a:b
)
)
),
TOCOL(
IFS(
i=MAX(
i
),
MAP(
x,
y,
LAMBDA(
a,
b,
TEXTJOIN(
{", ";" ; "},
,
a:b
)
)
)
),
2
)
)
Another one:
✅=LET(
f,
LAMBDA(
[n],
MAP(
B2:E5,
C3:F6,
LAMBDA(
a,
b,
IF(
n,
TEXTJOIN(
{", ";" ; "},
,
a:b
),
SUM(
a:b
)
)
)
)
),
TOCOL(
IFS(
f()=MAX(
f()
),
f(
1
)
),
2
)
)
Excel solution 5 for Max 2x2 Grid Sum, proposed by محمد حلمي:
=LET(
w,
LAMBDA(
i,
[e],
MAP(
B2:F6,
LAMBDA(
a,
IF(
i,
SUM(
OFFSET(
a,
,
,
2,
2
)
),
ARRAYTOTEXT(
OFFSET(
a,
e,
,
,
2
)
)
)
)
)
),
j,
w(
1
),
TOCOL(
IFS(
MAX(
j
)=j,
w(
0
)&" ; "&w(
0,
1
)
),
2
)
)
Excel solution 6 for Max 2x2 Grid Sum, proposed by محمد حلمي:
=REDUCE(
0,
B2:F6,
LAMBDA(
a,
v,
LET(
j,
TAKE(
a,
,
1
),
m,
MAX(
j
),
i,
SUM(
OFFSET(
v,
,
,
2,
2
)
),
r,
LAMBDA(
x,
ARRAYTOTEXT(
OFFSET(
v,
x,
,
,
2
)
)
),
w,
HSTACK(
i,
r(
0
)&" ; "& r(
1
)
),
IF(
COUNT(
v:F6
)=1,
DROP(
a,
,
1
),
IF(
i>=m,
VSTACK(
FILTER(
a,
j=m
),
w
),
a
)
)
)
)
)
Excel solution 7 for Max 2x2 Grid Sum, proposed by محمد حلمي:
=LET(
d,
B2:F6,
i,
IFNA(
d+C2:F6+B3:F6+C3:F6,
),
TOCOL(
IFS(
MAX(
i
)=i,
MAP(
d,
LAMBDA(
a,
LET(
r,
LAMBDA(
x,
ARRAYTOTEXT(
OFFSET(
a,
x,
,
,
2
)
)
),
r(
0
)&" ; "&r(
1
)
)
)
)
),
2
)
)
Excel solution 8 for Max 2x2 Grid Sum, proposed by Kris Jaganah:
=LET(
a,
B2:F6,
b,
MAP(
a,
LAMBDA(
x,
SUM(
OFFSET(
x,
0,
0,
2,
2
)
)
)
),
TOCOL(
IF(
b=MAX(
b
),
MAP(
a,
LAMBDA(
y,
TEXTJOIN(
{", ",
" ; "},
,
OFFSET(
y,
0,
0,
2,
2
)
)
)
),
z
),
3
)
)
Excel solution 9 for Max 2x2 Grid Sum, proposed by Julian Poeltl:
=LET(
A,
B2:F6,
S,
MAP(
A,
LAMBDA(
A,
SUM(
OFFSET(
A,
,
,
2,
2
)
)
)
),
C,
MAP(
A,
LAMBDA(
A,
TEXTJOIN(
"; ",
,
BYROW(
OFFSET(
A,
,
,
2,
2
),
LAMBDA(
A,
TEXTJOIN(
", ",
,
A
)
)
)
)
)
),
FILTER(
TOCOL(
C
),
TOCOL(
S
)=MAX(
S
)
)
)
Excel solution 10 for Max 2x2 Grid Sum, proposed by Timothée BLIOT:
=LET(
M,
MAKEARRAY(
4,
4,
LAMBDA(
x,
y,
SUM(
OFFSET(
B2:C3,
x-1,
y-1
)
)
)
),
TOCOL(
IF(
M=MAX(
M
),
MAKEARRAY(
4,
4,
LAMBDA(
x,
y,
LET(
O,
OFFSET(
B2:C3,
x-1,
y-1
),
ARRAYTOTEXT(
TAKE(
O,
1
)
)&" ; "&ARRAYTOTEXT(
TAKE(
O,
-1
)
)
)
)
),
1/0
),
3
)
)
Excel solution 11 for Max 2x2 Grid Sum, proposed by Nikola Z Grujicic - Nikola Ž Grujičić:
=LET(
niz,
B2:F6,
o,
ROWS(
niz
)-1,
p,
COLUMNS(
niz
)-1,
q,
SEQUENCE(
o*p
),
r,
MOD(
q,
),
s,
ROUNDUP(
q/o,
0
),
t,
IF(
r=0,
o,
r
),
y,
INDEX(
niz,
s,
t
)+INDEX(
niz,
s+1,
t
)+INDEX(
niz,
s,
t+1
)+INDEX(
niz,
s+1,
t+1
),
z,
MAX(
y
),
a,
IF(
y=z,
INDEX(
niz,
s,
t
)&", "&INDEX(
niz,
s+1,
t
)&"; "&INDEX(
niz,
s,
t+1
)&", "&INDEX(
niz,
s+1,
t+1
),
""
),
FILTER(
a,
a<>""
)
)
Excel solution 12 for Max 2x2 Grid Sum, proposed by Hussein SATOUR:
=LET(
v,
B2:F6,
a,
TOCOL(
MAP(
v,
LAMBDA(
x,
SUM(
OFFSET(
x,
,
,
2,
2
)
)
)
)
),
FILTER(
TOCOL(
MAP(
v,
LAMBDA(
x,
TEXTJOIN(
{", ",
"; ",
", "},
,
OFFSET(
x,
,
,
2,
2
)
)
)
)
),
a=MAX(
a
)
)
)
Excel solution 13 for Max 2x2 Grid Sum, proposed by Oscar Mendez Roca Farell:
=LET(
m,
MAP(
B2:E5,
LAMBDA(
a,
LET(
i,
INDEX(
B2:F6,
ROW(
a
)-{1; 0},
COLUMN(
a
)-{1,
0}
),
SUM(
i
)&"|"&TEXTJOIN(
{", ",
"; "},
,
i
)
)
)
),
t,
-TEXTBEFORE(
m,
"|"
),
TEXTAFTER(
TOCOL(
IFS(
t=MIN(
t
),
m
),
2
),
"|"
)
)
Excel solution 14 for Max 2x2 Grid Sum, proposed by Sunny Baggu:
=LET(
x, {1, 2} + SEQUENCE(5, , 0),
y, TRANSPOSE(x),
v, MAKEARRAY(5, 5, LAMBDA(r, c, INDEX(BYCOL(y, LAMBDA(a, SUM(INDEX(B2:G7, CHOOSEROWS(x, r), a)))), c))),
u, MAKEARRAY(
5,
5,
LAMBDA(r, c, INDEX(BYCOL(y, LAMBDA(a, ARRAYTOTEXT(TOROW(INDEX(B2:G7, CHOOSEROWS(x, r), a), , 1)))), c))
),
SUBSTITUTE(TOCOL(IF(v = MAX(v), u, NA()), 3), ", ", " ; ", 2)
)
Excel solution 15 for Max 2x2 Grid Sum, proposed by Sunny Baggu:
=LET(
t, B2:F6,
_a, MAP(t, LAMBDA(a, SUM(OFFSET(a, , , 2, 2)))),
_b, MAP(t, LAMBDA(a, ARRAYTOTEXT(OFFSET(a, , , 2, 2)))),
SUBSTITUTE(TOCOL(IF(_a = MAX(_a), _b, x), 3), ", ", " ; ", 2)
)
Excel solution 16 for Max 2x2 Grid Sum, proposed by LEONARD OCHEA 🇷🇴:
=LET(
d,
B2:F6,
s,
TOCOL(
MAP(
d,
LAMBDA(
x,
SUM(
OFFSET(
x,
,
,
2,
2
)
)
)
)
),
FILTER(
TOCOL(
MAP(
d,
LAMBDA(
x,
TEXTJOIN(
{", ";" ; "},
,
OFFSET(
x,
,
,
2,
2
)
)
)
)
),
s=MAX(
s
)
)
)
Excel solution 17 for Max 2x2 Grid Sum, proposed by Hamidi Hamid:
=LET(z,
B2:F6,
x,
TOCOL(MAP(IFERROR(((MAP(
B2:F6,
LAMBDA(
a;SUM(
OFFSET(
a,
,
,
2;2
)
)
)
)=MAX(
MAP(
z,
LAMBDA(
a;SUM(
OFFSET(
a,
,
,
2,
2
)
)
)
)
))*z),
0),
z,
LAMBDA(
a,
b,
IF(
a=0,
0,
TEXTJOIN(
{", ",
" ; "},
0,
OFFSET(
b,
,
,
2,
2
)
)
)
))),
FILTER(
x,
x<>0
))
Excel solution 18 for Max 2x2 Grid Sum, proposed by Andy Heybruch:
=LET(_tbl,B2:F6,
_sums,MAP(_tbl,LAMBDA(a,SUM(OFFSET(a,0,0,2,2)))),
_max,MAX(_sums),
FILTER(TOCOL(MAP(_tbl,LAMBDA(a,TEXTJOIN(" ; ",,TEXTJOIN(", ",,OFFSET(a,,,,2)),TEXTJOIN(", ",,OFFSET(a,1,,,2)))))),TOCOL(_sums=_max)))
Excel solution 19 for Max 2x2 Grid Sum, proposed by Bilal Mahmoud kh.:
=TEXTSPLIT(
TEXTJOIN(
"|",
TRUE,
LET(
a,
MAKEARRAY(
4,
4,
LAMBDA(
x,
y,
SUM(
OFFSET(
A1,
x,
y,
2,
2
)
)
)
),
b,
MAKEARRAY(
4,
4,
LAMBDA(
n,
m,
IF(
INDEX(
a,
n,
m
)=MAX(
a
),
TEXTJOIN(
";",
,
TEXTJOIN(
",",
,
OFFSET(
A1,
n,
m,
1,
2
)
),
TEXTJOIN(
",",
,
OFFSET(
A1,
n+1,
m,
1,
2
)
)
),
""
)
)
),
b
)
),
,
"|"
)
Excel solution 20 for Max 2x2 Grid Sum, proposed by Imam Hambali:
=LET(
a, TOCOL(B2:F6),
b, SEQUENCE(ROWS(a)),
c, HSTACK(b,DROP(b,1),DROP(b,5),DROP(b,6)),
d, FILTER(c,NOT(ISNA(TAKE(c,,-1)))*MOD(TAKE(c,,1),5)<>0),
f, BYROW(INDEX(a,d), LAMBDA(x, SUM(x))),
g, FILTER(INDEX(a,d), f=MAX(f)),
i, IF(MOD(SEQUENCE(,COLUMNS(g)),2),", ","; "),
BYROW(g&i, LAMBDA(x, LEFT(CONCAT(x), LEN(CONCAT(x))-2)))
)
Excel solution 21 for Max 2x2 Grid Sum, proposed by Eddy Wijaya:
=LET(
raw,
B2:F6,
genMap,
MAP(
raw,
LAMBDA(
m,
CONCAT(
HSTACK(
SUM(
OFFSET(
m,
,
,
2,
2
)
),
",",
TEXTJOIN(
",",
FALSE,
OFFSET(
m,
,
,
2,
2
)
)
)
)
)
),
adjMap,
TOCOL(
DROP(
genMap,
-1,
-1
)
),
getMax,
MAX(
BYROW(
adjMap,
LAMBDA(
r,
VALUE(
CHOOSECOLS(
TEXTSPLIT(
r,
","
),
1
)
)
)
)
),
filteredRes,
TOCOL(
BYROW(
adjMap,
LAMBDA(
r,
IF(
FIND(
getMax,
r
)=1,
MID(
r,
LEN(
TEXT(
getMax,
"0"
)
)+2,
LEN(
r
)
),
""
)
)
),
2
),
BYROW(
filteredRes,
LAMBDA(
r,
SUBSTITUTE(
TEXTBEFORE(
r,
",",
2
)&" ; "&TEXTAFTER(
r,
",",
2
),
",",
", "
)
)
)
)
Excel solution 22 for Max 2x2 Grid Sum, proposed by El Badlis Mohd Marzudin:
=LET(d,B2:F6,a,TOCOL(MAP(d,LAMBDA(x,TEXTJOIN({", "," ; "},,OFFSET(x,,,2,2))))),b,TOCOL(MAP(d,LAMBDA(x,SUM(OFFSET(x,,,2,2))))),FILTER(a,b=MAX(b)))
Excel solution 23 for Max 2x2 Grid Sum, proposed by Ricardo Alexis Domínguez Hernández:
=MAP(LET(b,LET(a,MAP(B2:F6,LAMBDA(x,SUM(OFFSET(x,0,0,2,2)))),TOCOL(IF(a=MAX(a),
MAP(B2:F6,LAMBDA(z,
TEXTJOIN(",",,OFFSET(z,,,2,2)))),0))),FILTER(b,b>0)),
LAMBDA(r,TEXTJOIN(" ; ",,BYROW(WRAPROWS(TEXTSPLIT(r,","),2),LAMBDA(x,TEXTJOIN(", ",,x))))))
Excel solution 24 for Max 2x2 Grid Sum, proposed by Dinc Doga:
=LET(
z,
B2:F6,
x,
TOCOL(
MAP(
IFERROR(
(MAP(
z,
LAMBDA(
a,
SUM(
OFFSET(
a,
0,
0,
2,
2
)
)
)
) = MAX(
MAP(
z,
LAMBDA(
a,
SUM(
OFFSET(
a,
0,
0,
2,
2
)
)
)
)
)) * z,
0
),
z,
LAMBDA(
a,
b,
IF(
a = 0,
0,
TEXTJOIN(
", ",
TRUE,
OFFSET(
b,
0,
0,
2,
2
)
)
)
)
)
),
FILTER(
x,
x <> 0
)
)
Excel solution 25 for Max 2x2 Grid Sum, proposed by Dinc Doga:
=LET(
niz, B2:F6,
o, ROWS(niz)-1,
p, COLUMNS(niz)-1,
q, SEQUENCE(o*p),
r, MOD(q-1, o)+1,
s, ROUNDUP(q/o, 0),
t, INDEX(niz, r, s),
y, t + INDEX(niz, r+1, s) + INDEX(niz, r, s+1) + INDEX(niz, r+1, s+1),
z, MAX(y),
a, IF(y=z, INDEX(niz, r, s) & ", " & INDEX(niz, r+1, s) & "; " & INDEX(niz, r, s+1) & ", " & INDEX(niz, r+1, s+1), ""),
FILTER(a, a<>"")
)
Excel solution 26 for Max 2x2 Grid Sum, proposed by Salvador Murillo Quezada:
=LET(m,MAP(B2:E5,LAMBDA(a,SUM(a,OFFSET(a,1,0),OFFSET(a,0,1),OFFSET(a,1,1)))), f,MAP(B2:E5,LAMBDA(a, TRIM(a)&", "&TRIM(OFFSET(a,0,1))&" ; "&TRIM(OFFSET(a,1,0))&", "&OFFSET(a,1,1) )),FILTER(TOCOL(f),TOCOL(m=MAX(m))) )
Solving the challenge of Max 2x2 Grid Sum with Python
Python solution 1 for Max 2x2 Grid Sum, proposed by Konrad Gryczan, PhD:
import pandas as pd
import numpy as np
import itertools
path = "514 Sub Grid Maximum Sum.xlsx"
input = pd.read_excel(path, usecols="B:F", header=None, skiprows=1)
input_mat = input.to_numpy()
test = pd.read_excel(path, usecols="H", nrows = 3)
indices = list(itertools.product(range(input_mat.shape[0] - 1), range(input_mat.shape[1] - 1)))
results = []
for i, j in indices:
sub_matrix = input_mat[i:i + 2, j:j + 2]
sub_sum = np.nansum(sub_matrix)
results.append({'matrix': sub_matrix, 'sum': sub_sum})
max_sum = max(res['sum'] for res in results)
max_subs = [res for res in results if res['sum'] == max_sum]
max_subs_str = [' ; '.join(', '.join(map(str, row)) for row in res['matrix']) for res in max_subs]
max_subs_df = pd.DataFrame({'Answer Expected': max_subs_str})
print(max_subs_df.equals(test)) # True
Solving the challenge of Max 2x2 Grid Sum with Python in Excel
Python in Excel solution 1 for Max 2x2 Grid Sum, proposed by Alejandro Campos:
grid = np.array([
[43, 48, 7, 47, 9],
[35, 13, 41, 24, 39],
[41, 9, 56, 92, 23],
[79, 5, 3, 7, 91],
[84, 45, 44, 41, 51]
])
max_values = []
for i in range(4): # 5 rows - 2x2 grid height + 1
for j in range(4): # 5 cols - 2x2 grid width + 1
current_sum = grid[i, j] + grid[i, j+1] + grid[i+1, j] + grid[i+1, j+1]
max_values.append((current_sum, i, j))
max_values = sorted(max_values, key=lambda x: x[0], reverse=True)[:3]
results = []
for value, i, j in max_values:
submatrix = grid[i:i+2, j:j+2].flatten().tolist()
results.append(submatrix)
results
Python in Excel solution 2 for Max 2x2 Grid Sum, proposed by Abdallah Ally:
df = xl("B2:F6", headers=False)
# Perform data wrangling
items = []
for i in df.index[:-1]:
for j in range(len(df.columns)-1):
values = list(df.iloc[i, j:j+2]) + list(df.iloc[i+1, j:j+2])
row1 = ', '.join([str(x) for x in values[:2]])
row2 = ', '.join([str(x) for x in values[2:]])
total = sum(values)
items.append([total, row1 + '; ' + row2])
max_total = max([item[0] for item in items])
result = [item[1] for item in items if item[0] == max_total]
result
Python in Excel solution 3 for Max 2x2 Grid Sum, proposed by Anshu Bantra:
df = xl("B2:F6", headers=False)
x, y = df.shape
lst=[]
for row_ in range(0, x-1):
for col_ in range(0, y-1):
_ = [f"{df.iloc[row_, col_]}, {df.iloc[row_, col_+1]}; {df.iloc[row_+1, col_]}, {df.iloc[row_+1, col_+1]}", df.iloc[row_, col_]+df.iloc[row_, col_+1]+df.iloc[row_+1, col_]+df.iloc[row_+1, col_+1]]
lst.append(_)
df_tst = pd.DataFrame(lst)
df_tst[df_tst[1]==df_tst[1].max()][0].values
Solving the challenge of Max 2x2 Grid Sum with R
R solution 1 for Max 2x2 Grid Sum, proposed by Konrad Gryczan, PhD:
library(tidyverse)
library(readxl)
path = "Excel/514 Sub Grid Maximum Sum.xlsx"
input = read_excel(path, range = "B2:F6", col_names = F) %>% as.matrix()
test = read_excel(path, range = "H1:H4") %>% arrange(`Answer Expected`)
indices = expand.grid(i = 1:(nrow(input) - 1), j = 1:(ncol(input) - 1))
results = indices %>%
pmap(function(i, j) {
sub_mat = input[i:(i + 1), j:(j + 1)]
list(matrix = sub_mat, sum = sum(sub_mat, na.rm = TRUE))
})
max_sum = max(map_dbl(results, "sum"))
max_subs = keep(results, ~ .x$sum == max_sum)
max_subs_str = map_chr(max_subs, ~ paste(apply(.x$matrix, 1, paste, collapse = ", "), collapse = " ; ")) %>%
tibble(`Answer Expected` = .) %>%
arrange(`Answer Expected`)
identical(max_subs_str, test)
#> [1] TRUE
&&
